2^x 1 2^x-1=20 114060-2^x+1+2^x-1=20

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2^x+1+2^x-1=20

2^x+1+2^x-1=20-Precalculus Solve for x 2^ (x1)= 2x−1 = 2 x 1 = Take the natural logarithm of both sides of the equation to remove the variable from the exponent ln(2x−1) = ln() ln ( 2 x 1) = ln x 2 x 1 10 x 1 2 x 2 x 1 2 x 2 40 40 9621 Intermediate Microeconomics from ECON 12 at Kyung Hee Study Resources Main Menu;

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Apply the law of Algebra ⇒ 2 x 1 (1 2 2 ) = 3 ⇒ 2 x 1 (1 4 ) = 3 ⇒ 2 x 1 x 5 = 3 ⇒ 2 x 1 = 64 = 2 x 2 x 2 x 2 x 2 x 2 ⇒ 2 x 1 = 2 6 if pX = pY then X will be equal to Y means X2 ^ { x 1 } 2 ^ { x 1 } = Similar Problems from Web Search 2^(x1)2^(x1)=1280 is the given equation Consider LHS 2^(x1)2^(x1) This can be written as (2^x/2)(2^x*2) Then

Incoming Term: 2^x+1+2^x-1=20, 2(3(x-1)-2(1-x))=20, (x+2)(x-2)(x+1)(x-1)+5x2=20,

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